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-rw-r--r--lib/stitches/contour_fill.py551
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diff --git a/lib/stitches/contour_fill.py b/lib/stitches/contour_fill.py
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+++ b/lib/stitches/contour_fill.py
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+from collections import namedtuple
+from itertools import chain
+
+import networkx as nx
+import numpy as np
+import trimesh
+from shapely.geometry import GeometryCollection, MultiPolygon, Polygon, LineString, Point
+from shapely.geometry.polygon import orient
+from shapely.ops import nearest_points
+from shapely.ops import polygonize
+
+from .running_stitch import running_stitch
+from ..stitch_plan import Stitch
+from ..utils import DotDict
+from ..utils.geometry import cut, reverse_line_string, roll_linear_ring
+from ..utils.geometry import ensure_geometry_collection, ensure_multi_polygon
+
+
+class Tree(nx.DiGraph):
+ # This lets us do tree.nodes['somenode'].parent instead of the default
+ # tree.nodes['somenode']['parent'].
+ node_attr_dict_factory = DotDict
+
+ def __init__(self, *args, **kwargs):
+ self.__node_num = 0
+ super().__init__(**kwargs)
+
+ def generate_node_name(self):
+ node = self.__node_num
+ self.__node_num += 1
+
+ return node
+
+
+nearest_neighbor_tuple = namedtuple(
+ "nearest_neighbor_tuple",
+ [
+ "nearest_point_parent",
+ "nearest_point_child",
+ "proj_distance_parent",
+ "child_node",
+ ],
+)
+
+
+def _offset_linear_ring(ring, offset, resolution, join_style, mitre_limit):
+ result = Polygon(ring).buffer(-offset, resolution, cap_style=2, join_style=join_style, mitre_limit=mitre_limit, single_sided=True)
+ result = ensure_multi_polygon(result)
+ rings = GeometryCollection([poly.exterior for poly in result.geoms])
+ rings = rings.simplify(0.01, False)
+
+ return _take_only_valid_linear_rings(rings)
+
+
+def _take_only_valid_linear_rings(rings):
+ """
+ Removes all geometries which do not form a "valid" LinearRing.
+
+ A "valid" ring is one that does not form a straight line.
+ """
+
+ valid_rings = []
+
+ for ring in ensure_geometry_collection(rings).geoms:
+ if len(ring.coords) > 3 or (len(ring.coords) == 3 and ring.coords[0] != ring.coords[-1]):
+ valid_rings.append(ring)
+
+ return GeometryCollection(valid_rings)
+
+
+def _orient_linear_ring(ring, clockwise=True):
+ # Unfortunately for us, Inkscape SVGs have an inverted Y coordinate.
+ # Normally we don't have to care about that, but in this very specific
+ # case, the meaning of is_ccw is flipped. It actually tests whether
+ # a ring is clockwise. That makes this logic super-confusing.
+ if ring.is_ccw != clockwise:
+ return reverse_line_string(ring)
+ else:
+ return ring
+
+
+def _orient_tree(tree, clockwise=True):
+ """
+ Orient all linear rings in the tree.
+
+ Since naturally holes have the opposite point ordering than non-holes we
+ make all lines within the tree uniform (having all the same ordering
+ direction)
+ """
+
+ for node in tree.nodes.values():
+ node.val = _orient_linear_ring(node.val, clockwise)
+
+
+def offset_polygon(polygon, offset, join_style, clockwise):
+ """
+ Convert a polygon to a tree of isocontours.
+
+ An isocontour is an offset version of the polygon's boundary. For example,
+ the isocontours of a circle are a set of concentric circles inside the
+ circle.
+
+ This function takes a polygon (which may have holes) as input and creates
+ isocontours until the polygon is filled completely. The isocontours are
+ returned as a Tree, with a parent-child relationship indicating that the
+ parent isocontour contains the child isocontour.
+
+ Arguments:
+ polygon - The shapely Polygon which may have holes
+ offset - The spacing between isocontours
+ join_style - Join style used when offsetting the Polygon border to create
+ isocontours. Can be round, mitered or bevel, as defined by
+ shapely:
+ https://shapely.readthedocs.io/en/stable/manual.html#shapely.geometry.JOIN_STYLE
+ clockwise - If True, isocontour points are in clockwise order; if False, counter-clockwise.
+
+ Return Value:
+ Tree - see above
+ """
+
+ ordered_polygon = orient(polygon, -1)
+ tree = Tree()
+ tree.add_node('root', type='node', parent=None, val=ordered_polygon.exterior)
+ active_polygons = ['root']
+ active_holes = [[]]
+
+ for hole in ordered_polygon.interiors:
+ hole_node = tree.generate_node_name()
+ tree.add_node(hole_node, type="hole", val=hole)
+ active_holes[0].append(hole_node)
+
+ while len(active_polygons) > 0:
+ current_poly = active_polygons.pop()
+ current_holes = active_holes.pop()
+
+ outer, inners = _offset_polygon_and_holes(tree, current_poly, current_holes, offset, join_style)
+ polygons = _match_polygons_and_holes(outer, inners)
+
+ for polygon in polygons.geoms:
+ new_polygon, new_holes = _convert_polygon_to_nodes(tree, polygon, parent_polygon=current_poly, child_holes=current_holes)
+
+ if new_polygon is not None:
+ active_polygons.append(new_polygon)
+ active_holes.append(new_holes)
+
+ for previous_hole in current_holes:
+ # If the previous holes are not
+ # contained in the new holes they
+ # have been merged with the
+ # outer polygon
+ if not tree.nodes[previous_hole].parent:
+ tree.nodes[previous_hole].parent = current_poly
+ tree.add_edge(current_poly, previous_hole)
+
+ _orient_tree(tree, clockwise)
+ return tree
+
+
+def _offset_polygon_and_holes(tree, poly, holes, offset, join_style):
+ outer = _offset_linear_ring(
+ tree.nodes[poly].val,
+ offset,
+ resolution=5,
+ join_style=join_style,
+ mitre_limit=10,
+ )
+
+ inners = []
+ for hole in holes:
+ inner = _offset_linear_ring(
+ tree.nodes[hole].val,
+ -offset, # take negative offset for holes
+ resolution=5,
+ join_style=join_style,
+ mitre_limit=10,
+ )
+ if not inner.is_empty:
+ inners.append(Polygon(inner.geoms[0]))
+
+ return outer, inners
+
+
+def _match_polygons_and_holes(outer, inners):
+ result = MultiPolygon(polygonize(outer.geoms))
+ if len(inners) > 0:
+ result = ensure_geometry_collection(result.difference(MultiPolygon(inners)))
+
+ return result
+
+
+def _convert_polygon_to_nodes(tree, polygon, parent_polygon, child_holes):
+ polygon = orient(polygon, -1)
+
+ if polygon.area < 0.1:
+ return None, None
+
+ valid_rings = _take_only_valid_linear_rings(polygon.exterior)
+
+ try:
+ exterior = valid_rings.geoms[0]
+ except IndexError:
+ return None, None
+
+ node = tree.generate_node_name()
+ tree.add_node(node, type='node', parent=parent_polygon, val=exterior)
+ tree.add_edge(parent_polygon, node)
+
+ hole_nodes = []
+ for hole in polygon.interiors:
+ hole_node = tree.generate_node_name()
+ tree.add_node(hole_node, type="hole", val=hole)
+ for previous_hole in child_holes:
+ if Polygon(hole).contains(Polygon(tree.nodes[previous_hole].val)):
+ tree.nodes[previous_hole].parent = hole_node
+ tree.add_edge(hole_node, previous_hole)
+ hole_nodes.append(hole_node)
+
+ return node, hole_nodes
+
+
+def _get_nearest_points_closer_than_thresh(travel_line, next_line, threshold):
+ """
+ Find the first point along travel_line that is within threshold of next_line.
+
+ Input:
+ travel_line - The "parent" line for which the distance should
+ be minimized to enter next_line
+ next_line - contains the next_line which need to be entered
+ threshold - The distance between travel_line and next_line needs
+ to below threshold to be a valid point for entering
+
+ Return value:
+ tuple or None
+ - the tuple structure is:
+ (point in travel_line, point in next_line)
+ - None is returned if there is no point that satisfies the threshold.
+ """
+
+ # We'll buffer next_line and find the intersection with travel_line.
+ # Then we'll return the very first point in the intersection,
+ # matched with a corresponding point on next_line. Fortunately for
+ # us, intersection of a Polygon with a LineString yields pieces of
+ # the LineString in the same order as the input LineString.
+ threshold_area = next_line.buffer(threshold)
+ portion_within_threshold = travel_line.intersection(threshold_area)
+
+ if portion_within_threshold.is_empty:
+ return None
+ else:
+ # Projecting with 0 lets us avoid distinguishing between LineString and
+ # MultiLineString.
+ parent_point = Point(portion_within_threshold.interpolate(0))
+ return nearest_points(parent_point, next_line)
+
+
+def _create_nearest_points_list(travel_line, tree, children, threshold, threshold_hard):
+ """Determine the best place to enter each of parent's children
+
+ Arguments:
+ travel_line - The "parent" line for which the distance should
+ be minimized to enter each child
+ children - children of travel_line that need to be entered
+ threshold - The distance between travel_line and a child should
+ to be below threshold to be a valid point for entering
+ threshold_hard - As a last resort, we can accept an entry point
+ that is this far way
+
+ Return value:
+ list of nearest_neighbor_tuple - indicating where to enter each
+ respective child
+ """
+
+ children_nearest_points = []
+
+ for child in children:
+ result = _get_nearest_points_closer_than_thresh(travel_line, tree.nodes[child].val, threshold)
+ if result is None:
+ # where holes meet outer borders a distance
+ # up to 2 * used offset can arise
+ result = _get_nearest_points_closer_than_thresh(travel_line, tree.nodes[child].val, threshold_hard)
+
+ proj = travel_line.project(result[0])
+ children_nearest_points.append(
+ nearest_neighbor_tuple(
+ nearest_point_parent=result[0],
+ nearest_point_child=result[1],
+ proj_distance_parent=proj,
+ child_node=child,
+ )
+ )
+
+ return children_nearest_points
+
+
+def _find_path_inner_to_outer(tree, node, offset, starting_point, avoid_self_crossing, forward=True):
+ """Find a stitch path for this ring and its children.
+
+ Strategy: A connection from parent to child is made as fast as possible to
+ reach the innermost child as fast as possible in order to stitch afterwards
+ from inner to outer.
+
+ This function calls itself recursively to find a stitch path for each child
+ (and its children).
+
+ Arguments:
+ tree - a Tree of isocontours (as returned by offset_polygon)
+ offset - offset that was passed to offset_polygon
+ starting_point - starting point for stitching
+ avoid_self_crossing - if True, tries to generate a path that does not
+ cross itself.
+ forward - if True, this ring will be stitched in its natural direction
+ (used internally by avoid_self_crossing)
+
+ Return value:
+ LineString -- the stitching path
+ """
+
+ current_node = tree.nodes[node]
+ current_ring = current_node.val
+
+ if not forward and avoid_self_crossing:
+ current_ring = reverse_line_string(current_ring)
+
+ # reorder the coordinates of this ring so that it starts with
+ # a point nearest the starting_point
+ start_distance = current_ring.project(starting_point)
+ current_ring = roll_linear_ring(current_ring, start_distance)
+ current_node.val = current_ring
+
+ # Find where along this ring to connect to each child.
+ nearest_points_list = _create_nearest_points_list(
+ current_ring,
+ tree,
+ tree[node],
+ threshold=1.5 * offset,
+ threshold_hard=2.05 * offset
+ )
+ nearest_points_list.sort(key=lambda tup: tup.proj_distance_parent)
+
+ result_coords = []
+ if not nearest_points_list:
+ # We have no children, so we're at the center of a spiral. Reversing
+ # the innermost ring gives a nicer visual appearance.
+ if not avoid_self_crossing:
+ current_ring = reverse_line_string(current_ring)
+ else:
+ # This is a recursive algorithm. We'll stitch along this ring, pausing
+ # to jump to each child ring in turn and sew it before continuing on
+ # this ring. We'll end back where we started.
+
+ result_coords.append(current_ring.coords[0])
+ distance_so_far = 0
+ for child_connection in nearest_points_list:
+ # Cut this ring into pieces before and after where this child will connect.
+ before, after = cut(current_ring, child_connection.proj_distance_parent - distance_so_far)
+ distance_so_far = child_connection.proj_distance_parent
+
+ # Stitch the part leading up to this child.
+ if before is not None:
+ result_coords.extend(before.coords)
+
+ # Stitch this child. The child will start and end in the same
+ # place, which should be close to our current location.
+ child_path = _find_path_inner_to_outer(
+ tree,
+ child_connection.child_node,
+ offset,
+ child_connection.nearest_point_child,
+ avoid_self_crossing,
+ not forward
+ )
+ result_coords.extend(child_path.coords)
+
+ # Skip ahead a little bit on this ring before resuming. This
+ # gives a nice spiral pattern, where we spiral out from the
+ # innermost child.
+ if after is not None:
+ skip, after = cut(after, offset)
+ distance_so_far += offset
+
+ current_ring = after
+
+ if current_ring is not None:
+ # skip a little at the end so we don't end exactly where we started.
+ remaining_length = current_ring.length
+ if remaining_length > offset:
+ current_ring, skip = cut(current_ring, current_ring.length - offset)
+
+ result_coords.extend(current_ring.coords)
+
+ return LineString(result_coords)
+
+
+def inner_to_outer(tree, offset, stitch_length, starting_point, avoid_self_crossing):
+ """Fill a shape with spirals, from innermost to outermost."""
+
+ stitch_path = _find_path_inner_to_outer(tree, 'root', offset, starting_point, avoid_self_crossing)
+ points = [Stitch(*point) for point in stitch_path.coords]
+ stitches = running_stitch(points, stitch_length)
+
+ return stitches
+
+
+def _reorder_linear_ring(ring, start):
+ distances = ring - start
+ start_index = np.argmin(np.linalg.norm(distances, axis=1))
+ return np.roll(ring, -start_index, axis=0)
+
+
+def _interpolate_linear_rings(ring1, ring2, max_stitch_length, start=None):
+ """
+ Interpolate between two LinearRings
+
+ Creates a path from start_point on ring1 and around the rings, ending at a
+ nearby point on ring2. The path will smoothly transition from ring1 to
+ ring2 as it travels around the rings.
+
+ Inspired by interpolate() from https://github.com/mikedh/pocketing/blob/master/pocketing/polygons.py
+
+ Arguments:
+ ring1 -- LinearRing start point will lie on
+ ring2 -- LinearRing end point will lie on
+ max_stitch_length -- maximum stitch length (used to calculate resampling accuracy)
+ start -- Point on ring1 to start at, as a tuple
+
+ Return value: Path interpolated between two LinearRings, as a LineString.
+ """
+
+ # Resample the two LinearRings so that they are the same number of points
+ # long. Then take the corresponding points in each ring and interpolate
+ # between them, gradually going more toward ring2.
+ #
+ # This is a little less accurate than the method in interpolate(), but several
+ # orders of magnitude faster because we're not building and querying a KDTree.
+
+ num_points = int(20 * ring1.length / max_stitch_length)
+ ring1_resampled = trimesh.path.traversal.resample_path(np.array(ring1.coords), count=num_points)
+ ring2_resampled = trimesh.path.traversal.resample_path(np.array(ring2.coords), count=num_points)
+
+ if start is not None:
+ ring1_resampled = _reorder_linear_ring(ring1_resampled, start)
+ ring2_resampled = _reorder_linear_ring(ring2_resampled, start)
+
+ weights = np.linspace(0.0, 1.0, num_points).reshape((-1, 1))
+ points = (ring1_resampled * (1.0 - weights)) + (ring2_resampled * weights)
+ result = LineString(points)
+
+ return result.simplify(0.1, False)
+
+
+def _check_and_prepare_tree_for_valid_spiral(tree):
+ """Check whether spiral fill is possible, and tweak if necessary.
+
+ Takes a tree consisting of isocontours. If a parent has more than one child
+ we cannot create a spiral. However, to make the routine more robust, we
+ allow more than one child if only one of the children has own children. The
+ other children are removed in this routine then. If the routine returns true,
+ the tree will have been cleaned up from unwanted children.
+
+ If even with these weaker constraints, a spiral is not possible, False is
+ returned.
+ """
+
+ def process_node(node):
+ children = set(tree[node])
+
+ if len(children) == 0:
+ return True
+ elif len(children) == 1:
+ child = children.pop()
+ return process_node(child)
+ else:
+ children_with_children = {child for child in children if tree[child]}
+ if len(children_with_children) > 1:
+ # Node has multiple children with children, so a perfect spiral is not possible.
+ # This False value will be returned all the way up the stack.
+ return False
+ elif len(children_with_children) == 1:
+ children_without_children = children - children_with_children
+ child = children_with_children.pop()
+ tree.remove_nodes_from(children_without_children)
+ return process_node(child)
+ else:
+ # None of the children has its own children, so we'll just take the longest.
+ longest = max(children, key=lambda child: tree[child]['val'].length)
+ shorter_children = children - {longest}
+ tree.remove_nodes_from(shorter_children)
+ return process_node(longest)
+
+ return process_node('root')
+
+
+def single_spiral(tree, stitch_length, starting_point):
+ """Fill a shape with a single spiral going from outside to center."""
+ return _spiral_fill(tree, stitch_length, starting_point, _make_spiral)
+
+
+def double_spiral(tree, stitch_length, starting_point):
+ """Fill a shape with a double spiral going from outside to center and back to outside. """
+ return _spiral_fill(tree, stitch_length, starting_point, _make_fermat_spiral)
+
+
+def _spiral_fill(tree, stitch_length, close_point, spiral_maker):
+ starting_point = close_point.coords[0]
+
+ rings = _get_spiral_rings(tree)
+ path = spiral_maker(rings, stitch_length, starting_point)
+ path = [Stitch(*stitch) for stitch in path]
+
+ return running_stitch(path, stitch_length)
+
+
+def _get_spiral_rings(tree):
+ rings = []
+
+ node = 'root'
+ while True:
+ rings.append(tree.nodes[node].val)
+
+ children = tree[node]
+ if len(children) == 0:
+ break
+ elif len(children) == 1:
+ node = list(children)[0]
+ else:
+ # We can only really fill a shape with a single spiral if each
+ # parent has only one child. We'll do our best though, because
+ # that is probably more helpful to the user than just refusing
+ # entirely. We'll pick the child that's closest to the center.
+ parent_center = rings[-1].centroid
+ node = min(children, key=lambda child: parent_center.distance(tree.nodes[child].val.centroid))
+
+ return rings
+
+
+def _make_fermat_spiral(rings, stitch_length, starting_point):
+ forward = _make_spiral(rings[::2], stitch_length, starting_point)
+ back = _make_spiral(rings[1::2], stitch_length, starting_point)
+ back.reverse()
+
+ return chain(forward, back)
+
+
+def _make_spiral(rings, stitch_length, starting_point):
+ path = []
+
+ for ring1, ring2 in zip(rings[:-1], rings[1:]):
+ spiral_part = _interpolate_linear_rings(ring1, ring2, stitch_length, starting_point)
+ path.extend(spiral_part.coords)
+
+ return path